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Precalculus Calculator Online

Precalculus Calculator Online

Precalculus calculator online,Example Problems for Online Precalculas Calculator


Precalculus calculator online is one interesting topics in mathematics. Precalculus calculator online is used to solve different types of precalculus problems. Calculator is a web-based tool to solve the problems. Online is nothing but the one computer is connected with another computer through a network or a cable. Here we solve some precalculus calculator online problems.

Example Problems for Online Precalculas Calculator:

Example problems for online precalculas calculator are given below:

Example 1:

Solve the quadratic equation x2 + x 42.

Solution:

Let f(x) = x2 + x 42

Now, plug f(x) = 0

x2 6x +7x 42 = 0

x(x 6) + 7(x 6) = 0

(x 6)(x + 7) = 0

x = 6; x = 7

The roots are x = 6, x = 7.

Example 2:

Solve 12x 4y + 20 = 0. Find the slope and y-intercept for the given straight line.

Solution:

12x 4y + 20 = 0

4y = 12x 20

Dividing by 4,

y = 3x + 5 (1)

General form of a straight line is,

y = mx + b (2)

Where, m = slope of a line,

b = y intercept of a line,

Here, y = 3x + 5

Compare the equation (1) and (2), we get,

Slope of the line m = 3,

y-intercept of the line b = 5.

Additional Example Problems for Precalculus Calculator Online

Additional Example problems for online precalculas calculator are given below:

Example 3:

Find the center and radius of the circle for the given standard equation x2 + 10x + y2 8y 7 = 0

Solution:

Given: x2 + 10x + y2 8y 7 = 0

Standard equation for circle with center (a, b) and radius r is,

(x - a)2 + (y - b)2 = r2

Completing the x terms and y terms on the square that gives

(x2 + 10x + 10) + (y2 - 8y + 8) 7 - 10 - 8 = 0

(x2 + 10x +10) + (y2 - 8y + 8) = 7 + 10 + 8

(x + 10)2 + (y - 8)2 = 25,

Solution to the center of the circle is (10, -8), and the radius is 5.

Example 4:

Find the vertex of the parabola y = 5x2 30x + 9

Solution:

General form:

x-coordinate for the vertex of the parabola is x = -b/2a,

y-coordinate is find by substitute the value for x into f(x)

Given: y = 5x2 30x + 9

We know that x = -b/2a,

Here a = 5, b = -30

So that, X = -b/2a = -(-30)/(2*5) = 3

And then y = 5(32) 30(3) + 9 = 45 90 + 9 = -36

Solution to the problem is x = 3 and y = -36.

by: Smith
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Precalculus Calculator Online